[ub] Justification for < not being a total order on pointers?
Gabriel Dos Reis
gdr at axiomatics.org
Thu Oct 17 17:19:09 CEST 2013
Nevin Liber <nevin at eviloverlord.com> writes:
| But, even if segmented architectures, unlikely though it is, do come back, the
| ordering problem still has to be addressed, as std::less<T*> is required to
| totally order pointers. I just want operator< to be an alternate spelling for
| that property.
I will repeat this again: std::less<T*> is absolutely not a problem,
because this
return intptr_t(p) < intptr_t(q);
is valid and portable definition that requires no other special handling.
-- Gaby
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