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Section: 31.12.6 [fs.class.path] Status: WP Submitter: Jiang An Opened: 2022-01-02 Last modified: 2022-02-10
Priority: Not Prioritized
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Discussion:
The hash support of std::filesystem::path is provided by std::filesystem::hash_value, but the specialization std::hash<std::filesystem::path> is currently disabled. IMO the specialization should be enabled, and its operator() should return the same value as hash_value.
[2022-01-15; Daniel provides wording]
Previous resolution [SUPERSEDED]:
This wording is relative to N4901.
Modify 31.12.4 [fs.filesystem.syn], header <filesystem> synopsis, as indicated:
#include <compare> // see 17.11.1 [compare.syn] namespace std::filesystem { // 31.12.6 [fs.class.path], paths class path; // 31.12.6.8 [fs.path.nonmember], path non-member functions void swap(path& lhs, path& rhs) noexcept; size_t hash_value(const path& p) noexcept; […] } // [fs.path.hash], hash support namespace std { template<class T> struct hash; template<> struct hash<filesystem::path>; }Following subclause 31.12.6.8 [fs.path.nonmember], introduce a new subclause [fs.path.hash], as indicated:
29.12.6.? Hash support [fs.path.hash]
template<> struct hash<filesystem::path>;-?- For an object p of type filesystem::path, hash<filesystem::path>()(p) shall evaluate to the same result as hash_value(p).
[2022-01-18; Daniel improves wording based on reflector discussion feedback]
[2022-01-30; Reflector poll]
Set status to Tentatively Ready after five votes in favour during reflector poll.
[2022-02-10 Approved at February 2022 virtual plenary. Status changed: Tentatively Ready → WP.]
Proposed resolution:
This wording is relative to N4901.
Modify 31.12.4 [fs.filesystem.syn], header <filesystem> synopsis, as indicated:
#include <compare> // see 17.11.1 [compare.syn] namespace std::filesystem { // 31.12.6 [fs.class.path], paths class path; // 31.12.6.8 [fs.path.nonmember], path non-member functions void swap(path& lhs, path& rhs) noexcept; size_t hash_value(const path& p) noexcept; […] } // [fs.path.hash], hash support namespace std { template<class T> struct hash; template<> struct hash<filesystem::path>; }
Following subclause 31.12.6.8 [fs.path.nonmember], introduce a new subclause [fs.path.hash], as indicated:
29.12.6.? Hash support [fs.path.hash]
template<> struct hash<filesystem::path>;-?- For an object p of type filesystem::path, hash<filesystem::path>()(p) evaluates to the same result as filesystem::hash_value(p).