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3307. std::allocator<void>().allocate(n)

Section: 20.2.10 [default.allocator] Status: C++20 Submitter: Jonathan Wakely Opened: 2019-10-25 Last modified: 2021-02-25

Priority: 0

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Discussion:

In C++20 the std::allocator<void> explicit specialization is gone, which means it uses the primary template, which has allocate and deallocate members.

Although it's implied by the use of sizeof(T), std::allocator<T>::allocate doesn't have an explicit precondition that the value type is complete.

[2019-11 Status to 'Ready' in Monday issue prioritization in Belfast]

Proposed resolution:

This wording is relative to N4835.

1. Modify 20.2.10.2 [allocator.members] as indicated:

   [[nodiscard]] constexpr T* allocate(size_t n);
   

   -?- Mandates: T is not an incomplete type (6.8 [basic.types]).

   -2- Returns: A pointer to the initial element of an array of storage of size n * sizeof(T), aligned appropriately for objects of type T.

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