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Section: 26.7.6.2 [range.ref.view] Status: C++20 Submitter: Casey Carter Opened: 2018-12-09 Last modified: 2021-06-06
Priority: 0
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Discussion:
In the specification of view::all in 26.7.6 [range.all], paragraph 2.2 states that view::all(E) is sometimes expression-equivalent to "ref-view{E} if that expression is well-formed". Unfortunately, the expression ref-view{E} is never well-formed: ref-view's only non-default constructor is a perfect-forwarding-ish constructor template that accepts only arguments that convert to lvalues of the ref-view's template argument type, and either do not convert to rvalues or have a better lvalue conversion (similar to the reference_wrapper converting constructor (22.10.6.2 [refwrap.const]) after issue 2993).
Presumably this breakage was not intentional, and we should add a deduction guide to enable class template argument deduction to function as intended by paragraph 2.2.
[2018-12-16 Status to Tentatively Ready after six positive votes on the reflector.]
Proposed resolution:
This wording is relative to N4791.
Modify the ref-view class synopsis in [ranges.view.ref] as follows:
namespace std::ranges { template<Range R> requires is_object_v<R> class ref-view : public view_interface<ref-view<R>> { […] }; template<class R> ref_view(R&) -> ref_view<R>; }