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3170. is_always_equal added to std::allocator makes the standard library treat derived types as always equal

Section: 20.2.10 [default.allocator] Status: WP Submitter: Billy O'Neal III Opened: 2018-11-29 Last modified: 2020-11-09

Priority: 2

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Discussion:

I (Billy O'Neal) attempted to change MSVC++'s standard library to avoid instantiating allocators' operator== for allocators that are declared is_always_equal to reduce the number of template instantiations emitted into .objs.

In so doing I introduced an unrelated bug related to POCMA handling, but it brought my attention to this allocator. This allocator doesn't meet the allocator requirements because it is getting std::allocator's operator== and operator!= which don't compare the root member. However, if this had been a conforming C++14 allocator with its own == and != we would still be treating it as is_always_equal, as it picks that up by deriving from std::allocator.

std::allocator doesn't actually need is_always_equal because the defaults provided by allocator_traits will say true_type for it, since implementers don't make std::allocator stateful.

Billy O'Neal thinks this is NAD on the grounds that we need to be able to add things or change the behavior of standard library types.

Stephan T Lavavej thinks we should resolve this anyway because we don't know of an implementation for which this would change the default answer provided by allocator_traits.

[2019-02 Priority set to 2 after reflector discussion]

This wording is relative to N4778.

1. Modify 20.2.10 [default.allocator] as follows:

   -1- All specializations of the default allocator satisfy the allocator completeness requirements (16.4.4.6.2 [allocator.requirements.completeness]).

   namespace std {
     template<class T> class allocator {
     public:
       using value_type = T;
       using size_type = size_t;
       using difference_type = ptrdiff_t;
       using propagate_on_container_move_assignment = true_type;
       using is_always_equal = true_type;
       constexpr allocator() noexcept;
       constexpr allocator(const allocator&) noexcept;
       template<class U> constexpr allocator(const allocator<U>&) noexcept;
       ~allocator();
       allocator& operator=(const allocator&) = default;
       [[nodiscard]] T* allocate(size_t n);
       void deallocate(T* p, size_t n);
     };
   }
   

   -?- allocator_traits<allocator<T>>::is_always_equal::value is true for any T.

[2019-07 Cologne]

Jonathan provides updated wording.

[2020-10-02; Issue processing telecon: Moved to Tentatively Ready.]

[2020-11-09 Approved In November virtual meeting. Status changed: Tentatively Ready → WP.]

Proposed resolution:

This wording is relative to N4820.

1. Modify 20.2.10 [default.allocator] as follows:

   -1- All specializations of the default allocator satisfy the allocator completeness requirements (16.4.4.6.2 [allocator.requirements.completeness]).

   namespace std {
     template<class T> class allocator {
     public:
       using value_type = T;
       using size_type = size_t;
       using difference_type = ptrdiff_t;
       using propagate_on_container_move_assignment = true_type;
       using is_always_equal = true_type;
       constexpr allocator() noexcept;
       constexpr allocator(const allocator&) noexcept;
       template<class U> constexpr allocator(const allocator<U>&) noexcept;
       ~allocator();
       allocator& operator=(const allocator&) = default;
       [[nodiscard]] T* allocate(size_t n);
       void deallocate(T* p, size_t n);
     };
   }
   

   -?- allocator_traits<allocator<T>>::is_always_equal::value is true for any T.

2. Add a new subclause in Annex D after D.15 [depr.str.strstreams]:

   D.? The default allocator [depr.default.allocator]

   -?- The following member is defined in addition to those specified in 20.2.10 [default.allocator]:

   namespace std {
     template <class T> class allocator {
     public:
       using is_always_equal = true_type;
     };
   }