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Section: 16.4.4.6 [allocator.requirements], 20.2.9.2 [allocator.traits.types] Status: C++17 Submitter: Howard Hinnant Opened: 2015-01-18 Last modified: 2017-07-30
Priority: 0
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Discussion:
Table 28 — "Allocator requirements" says that X::is_always_equal has a default value of is_empty<X>, and this is consistent with the return type description:
Identical to or derived from true_type or false_type
is_empty<X> is guaranteed to be derived from either true_type or false_type. So far so good.
20.2.9.2 [allocator.traits.types]/p10 says:typedef see below is_always_equal;Type: Alloc::is_always_equal if the qualified-id Alloc::is_always_equal is valid and denotes a type (14.8.2); otherwise is_empty<Alloc>::type.
This is subtly different than what Table 28 says is the default: is_empty<Alloc>::type is not is_empty<Alloc>, but is rather one of true_type or false_type.
There are two ways to fix this:Change Table 28 to say: is_empty<X>::type.
orChange 20.2.9.2 [allocator.traits.types]/p10:
Type: Alloc::is_always_equal if the qualified-id Alloc::is_always_equal is valid and denotes a type (14.8.2); otherwise is_empty<Alloc>
::type.
Both options are correct, and I see no reason to prefer one fix over the other. But Table 28 and 20.2.9.2 [allocator.traits.types]/p10 should be consistent with one another.
[2015-02 Cologne]
DK: We should accept the first bullet. GR: Why does is_empty even have a type member? AM: All type traits have a type member. I agree with DK's preference for the first type.
Proposed resolution:
This wording is relative to N4296.
Change 16.4.4.6 [allocator.requirements], Table 28 — "Allocator requirements" as presented:
Table 28 — Allocator requirements Expression Return type Assertion/note
pre-/post-conditionDefault … X::is_always_equal Identical to or derived
from true_type or
false_type[…] is_empty<X>::type …