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Section: 21.3.4 [meta.help] Status: C++11 Submitter: Alisdair Meredith Opened: 2009-03-11 Last modified: 2016-01-28
Priority: Not Prioritized
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Discussion:
Addresses UK 205 [CD1]
integral_constant objects should be usable in integral-constant-expressions. The addition to the language of literal types and the enhanced rules for constant expressions make this possible.
[ Batavia (2009-05): ]
We agree that the static data member ought be declared constexpr, but do not see a need for the proposed operator value_type(). (A use case would be helpful.) Move to Open.
[ 2009-05-23 Alisdair adds: ]
The motivating case in my mind is that we can then use true_type and false_type as integral Boolean expressions, for example inside a static_assert declaration. In that sense it is purely a matter of style.
Note that Boost has applied the non-explicit conversion operator for many years as it has valuable properties for extension into other metaprogramming libraries, such as MPL. If additional rationale is desired I will poll the Boost lists for why this extension was originally applied. I would argue that explicit conversion is more appropriate for 0x though.
[ 2009-07-04 Howard adds: ]
Here's a use case which demonstrates the syntactic niceness which Alisdair describes:
#define requires(...) class = typename std::enable_if<(__VA_ARGS__)>::type template <class T, class U, requires(!is_lvalue_reference<T>() || is_lvalue_reference<T>() && is_lvalue_reference<U>()), requires(is_same<typename base_type<T>::type, typename base_type<U>::type>)> inline T&& forward(U&& t) { return static_cast<T&&>(t); }
[ 2009-07 post-Frankfurt: ]
Move to Tentatively Ready.
[ 2009 Santa Cruz: ]
Moved to Ready for this meeting.
Proposed resolution:
Add to the integral_constant struct definition in 21.3.4 [meta.help]:
template <class T, T v> struct integral_constant { static constexpr T value = v; typedef T value_type; typedef integral_constant<T,v> type; constexpr operator value_type() { return value; } };