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From: "Malcolm Cohen" <malcolm@nag-j.co.jp>
To: "WG5" <sc22wg5@open-std.org>
Subject: More comments on draft Corrigendum 4
Date: Sat, 6 Feb 2016 11:57:23 +0900
Organization: NAG
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Hi folks,

Sorry to keep dribbling these out, but I am constructing a new standing =
document 18 (Interpretation Insert Pages), and that is throwing up more =
issues.

(17) In the edit for F08/0144 at [178:18+], the problem here is that =
this is inserting stuff in the middle of the changes from another =
Corrigendum, which in fact has already deleted the bullet point that =
this is trying to insert stuff after!  This would be better located at =
[178:16+], and change =1B$B!H=1B(Bat the end of the bullet =
list=1B$B!I=1B(B to =1B$B!H=1B(Bafter the bullet item beginning =
=1B$B!F=1B(BAn input/output statement=1B$B!G=1B(B.

(18) In the edit for F08/0134 at [190:5+], the constraint is properly =
worded so that the restriction to the syntax rule =
=1B$B!H=1B(B(R859)=1B$B!I=1B(B is unnecessary.  It is also harmless.

...and now I have to prepare to catch a plane; so probably more somewhat =
later.

Cheers,
--=20
.........................Malcolm.

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<HTML><HEAD></HEAD>
<BODY dir=3Dltr>
<DIV dir=3Dltr>
<DIV style=3D"FONT-SIZE: 12pt; FONT-FAMILY: 'Calibri'; COLOR: #000000">
<DIV>Hi folks,</DIV>
<DIV>&nbsp;</DIV>
<DIV>Sorry to keep dribbling these out, but I am constructing a new =
standing=20
document 18 (Interpretation Insert Pages), and that is throwing up more=20
issues.</DIV>
<DIV>&nbsp;</DIV>
<DIV>(17) In the edit for F08/0144 at [178:18+], the problem here is =
that this=20
is inserting stuff in the middle of the changes from another =
Corrigendum, which=20
in fact has already deleted the bullet point that this is trying to =
insert stuff=20
after!&nbsp; This would be better located at [178:16+], and change =
=1B$B!H=1B(Bat the end=20
of the bullet list=1B$B!I=1B(B to =1B$B!H=1B(Bafter the bullet item =
beginning =1B$B!F=1B(BAn input/output=20
statement=1B$B!G=1B(B.</DIV>
<DIV>&nbsp;</DIV>
<DIV>(18) In the edit for F08/0134 at [190:5+], the constraint is =
properly=20
worded so that the restriction to the syntax rule =
=1B$B!H=1B(B(R859)=1B$B!I=1B(B is unnecessary.&nbsp;=20
It is also harmless.</DIV>
<DIV>&nbsp;</DIV>
<DIV>...and now I have to prepare to catch a plane; so probably more =
somewhat=20
later.</DIV>
<DIV>&nbsp;</DIV>
<DIV>Cheers,</DIV>
<DIV>-- </DIV>
<DIV>.........................Malcolm.</DIV>
<DIV>&nbsp;</DIV></DIV></DIV></BODY></HTML>

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